NEETChemistryChemical Equilibrium
The thermal decomposition of calcium carbonate occurs in a closed vessel according to the following equation: CaCO ₃( s ) CaO ( s ) + CO ₂( g ) If 2.0 moles of CaCO ₃ are placed in a 10.0 L closed vessel and allowed to reach equilibrium at a certain temperature, the equilibrium constant K_c for the reaction is found to be 0.05 M . What is the equilibrium concentration of CO ₂( g ) ?
Options
- A0.2 M
- B0.5 M
- C0.005 M
- D0.05 M
Correct answer
D. 0.05 M
Step-by-step solution
The given reaction is a heterogeneous equilibrium: CaCO ₃( s ) CaO ( s ) + CO ₂( g ) By convention, the active masses (molar concentrations) of pure solids and pure liquids are taken as unity and are excluded from the equilibrium constant expression. Therefore, the equilibrium constant K_c depends only on the concentration of the gaseous product: K_c = [ CO ₂( g )] Given that K_c = 0.05 M , the equilibrium concentration of CO ₂( g ) is simply equal to the value of K_c . [ CO ₂( g )] = 0.05 M The initial moles of Ca