NEETChemistryChemical Equilibrium
Match List-I with List-II: List-I (Reaction) List-II ( K_p K_c ratio) (A) H ₂ (g) + I ₂ (g) 2 HI(g) (I) (RT)⁻² (B) N ₂ (g) + 3 H ₂ (g) 2 NH ₃ (g) (II) 1 (C) CaCO ₃ (s) CaO(s) + CO ₂ (g) (III) (RT)⁻¹ (D) 2 NO ₂ (g) N ₂ O ₄ (g) (IV) RT Choose the correct answer from the options given below:
Options
- A(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
- B(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- C(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- D(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Correct answer
D. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Step-by-step solution
The relationship between K_p and K_c is given by K_p = K_c(RT)^ n_g , which rearranges to K_p K_c = (RT)^ n_g . For (A) H ₂ (g) + I ₂ (g) 2 HI(g) , n_g = 2 - 2 = 0 . Thus, K_p K_c = (RT)^0 = 1 . For (B) N ₂ (g) + 3 H ₂ (g) 2 NH ₃ (g) , n_g = 2 - 4 = -2 . Thus, K_p K_c = (RT)⁻² . For (C) CaCO ₃ (s) CaO(s) + CO ₂ (g) , only gaseous species are considered. n_g = 1 - 0 = 1 . Thus, K_p K_c = (RT)^1 = RT . For (D) 2 NO ₂ (g) N ₂ O ₄ (g) , n_g = 1 - 2 = -1 . Thus, K_p K_c = (RT)⁻¹ . Therefore, the correct matching is (A)-