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For the thermal decomposition of solid ammonium carbamate, NH ₂ COONH ₄ (s) 2 NH ₃ (g) + CO ₂ (g) the ratio of the equilibrium constants K_p K_c is:

Options

  1. A(RT)^2
  2. B(RT)^3
  3. C(RT)^ -3
  4. D1

Correct answer

B. (RT)^3

Step-by-step solution

For the given heterogeneous reaction: NH ₂ COONH ₄ (s) 2 NH ₃ (g) + CO ₂ (g) The relationship between K_p and K_c is given by K_p = K_c(RT)^ n_g . Here, n_g is the difference between the number of moles of gaseous products and gaseous reactants. Moles of gaseous products = 2 (from NH ₃) + 1 (from CO ₂) = 3 Moles of gaseous reactants = 0 (since ammonium carbamate is a solid and its active mass is taken as unity). Therefore, n_g = 3 - 0 = 3 . Substituting this value, we get K_p = K_c(RT)^3 , which gives the ratio K_p

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