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NEETChemistryChemical Equilibrium

Match List-I with List-II regarding the optimum conditions for maximizing the forward reaction according to Le Chatelier's principle. List-I (Reactions) List-II (Favourable Conditions) (A) 2 SO ₂( g ) + O ₂( g ) 2 SO ₃( g ); H (I) High temperature, High pressure (B) 2 O ₃( g ) 3 O ₂( g ); H (II) High temperature, Low pressure (C) N ₂( g ) + 2 O ₂( g ) 2 NO ₂( g ); H > 0 (III) Low temperature, High pressure (D) PCl ₅(

Options

  1. A(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  2. B(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  3. C(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. D(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

Correct answer

C. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Step-by-step solution

According to Le Chatelier's principle, an increase in temperature favours endothermic reactions ( H > 0 ), while a decrease in temperature favours exothermic reactions ( H (A) 2 SO ₂( g ) + O ₂( g ) 2 SO ₃( g ); H Exothermic and n _g = 2 - 3 = -1 . Favourably shifted forward by Low temperature and High pressure. Matches with (III). (B) 2 O ₃( g ) 3 O ₂( g ); H Exothermic and n _g = 3 - 2 = +1 . Favourably shifted forward by Low temperature and Low pressure. Matches with (IV). (C) N ₂( g ) + 2 O ₂( g ) 2 NO ₂( g );

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