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NEETChemistryChemical Equilibrium

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): For the reaction CaCO ₃( s ) CaO ( s ) + CO ₂( g ) at 1000 ~K , the numerical value of K_P is less than K_C . Reason (R): For the given reaction, the change in the number of moles of gaseous species ( n_g ) is positive and at 1000 ~K , the value of RT is greater than 1 . In the light of the above s

Options

  1. ABoth (A) and (R) are correct and (R) is the correct explanation of (A)
  2. BBoth (A) and (R) are correct but (R) is not the correct explanation of (A)
  3. C(A) is correct but (R) is not correct
  4. D(A) is not correct but (R) is correct

Correct answer

D. (A) is not correct but (R) is correct

Step-by-step solution

The relationship between K_P and K_C is given by K_P = K_C(RT)^ n_g . For the reaction CaCO ₃( s ) CaO ( s ) + CO ₂( g ) , the change in gaseous moles is: n_g = n_ g( products ) - n_ g( reactants ) = 1 - 0 = 1 . Since n_g = 1 , we have K_P = K_C(RT)^1 . At 1000 ~K , the value of R is approximately 0.0831 ~L~bar~K⁻¹~mol⁻¹ , so RT = 0.0831 1000 = 83.1 , which is greater than 1 . Because RT > 1 and n_g = 1 , it follows that K_P = K_C 83.1 , meaning K_P > K_C . Thus, Assertion (A) is incorrect because it states K_P 1 .

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