NEETChemistryChemical Equilibrium
Given the equilibrium constants for the following base reactions: X Y ; K Z W ; K' Match the reactions in List-I with their corresponding equilibrium constants in List-II. List-I List-II (A) Y X (I) K^2 (B) 2X 2Y (II) 1 K (C) 1 2 Y 1 2 X (III) K K' (D) X + Z Y + W (IV) 1 K Choose the correct answer from the options given below:
Options
- A(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- B(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
- C(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
- D(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Correct answer
D. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Step-by-step solution
For a base reaction X Y with equilibrium constant K : (A) When the reaction is reversed ( Y X ), the new equilibrium constant is the reciprocal of the original. Thus, K_ new = 1 K . Matches with (II). (B) When the reaction is multiplied by 2 ( 2X 2Y ), the new equilibrium constant is the original raised to the power of 2. Thus, K_ new = K^2 . Matches with (I). (C) When the reaction is reversed and multiplied by 1 2 ( 1 2 Y 1 2 X ), the new equilibrium constant is the reciprocal raised to the power of 1 2 . Thus, K_