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NEET2014ChemistryChemical EquilibriumActual

The equilibrium constant for the reaction, 1 2 H _ 2(g) + 1 2 I _ 2(g) HI _ (g) is K_c . Equilibrium constant for the reaction, 2 HI _ (g) H _ 2(g) + I _ 2(g) will be

Options

  1. A1 / K_c
  2. B1 / (K_c )^2
  3. C2 / K_c
  4. D2 / (K_c )^2

Correct answer

B. 1 / (K_c )^2

Step-by-step solution

The given reaction is, 1 2 H _ 2(g) + 1 2 I _ 2(g) HI _ (g) Hence, K_c= [ HI ] [ H ₂ ]^ 1 / 2 [ I ₂ ]^ 1 / 2 Now, reverse the eqn. (i) and multiply by 2 , we get 2 HI H _ 2(g) + I _ 2(g) Hence, K_c^ = [ H ₂ ] [ I ₂ ] [ HI ]^2 Equating equations (ii) and (iii), we get K_c^ = 1 (K_c )^2

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