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NEET2009ChemistryChemical EquilibriumActual

The equilibrium constant for mutarotation -D Glucose -D Glucose is 1.8 . What percentage of form remains at equilibrium?

Options

  1. A35.7
  2. B64.3
  3. C55.6
  4. D44.4

Correct answer

A. 35.7

Step-by-step solution

-D glucose -D glucose array lcc Initial & 1 & 0 At equilibrium & 1- & array K= 1- =1.8 Solving =0.6421- =0.358 Percent of -D glucose remaining at equilibrium =35.8 % .

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