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NEETChemistryp Block Elements (Group 13 & 14)

Observe the following statements regarding ( C ₆₀ ). i. All carbons are (s p^2 )-hybridised. ii. It contains 12 rings of five carbons each and 20 rings of six carbons each. iii. It is a non-aromatic compound. iv. It is pure form of carbon. v. ( C - C ) bond lengths in it are 143.5 and (138.3 pm ). vi. It is prepared by heating graphite in an electric arc in the presence of oxygen. The correct statements are

Options

  1. Ai, ii, iii, iv, v
  2. Bi, ii, iv, v only
  3. Ci, ii, iv, vi only
  4. Di, ii, iii only

Correct answer

B. i, ii, iv, v only

Step-by-step solution

In ( C ₆₀ ), all carbon atoms are (s p^2 )-hybridised. It contains 12 rings of five carbon each and 20 rings of six carbon each. It is anti-aromatic with spherically surrounded by ( )-electrons. It is a pure form of carbon. ( C - C ) bond length in it are 143.5 and (138.3 pm ). It is prepared by heating graphite in an electric arc under inert condition (He gas). Thus, statements (i), (ii), (iv) and (v) are correct.

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