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NEETChemistryp Block Elements (Group 13 & 14)

Match the following. Column-1 Reaction Column-2 Main product A B 2 H 6 + 2 CO ⟶ I B 2 O 3 B B 2 H 6 + 3 O 2 ⟶ II 2 BH 3 · CO C B 2 H 6 + 6 H 2 O ⟶ III 2 H 3 BO 3 IV 2 BH 2 ( CO ) V 2 HBO 2 The correct match is

Options

  1. AA B C IV I III
  2. BA B C II III V
  3. CA B C IV III I .
  4. DA .B C II I III

Correct answer

D. A .B C II I III

Step-by-step solution

Boron hydride is an electron deficient species so, it act like and Lewis acid and carbon monoxide act as a Lewis base and form a co-ordinate bond. B 2 H 6 + CO   ⟶   2 BH 3 · CO It is oxidised with air. B 2 H 6 + 3 O 2 ⟶   B 2 O 3   +   3   H 2 O It is hydrolysed with water to give B 2 H 6 + 6 H 2 O ⟶   2 H 3 BO 3   +   6   H 2

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