NEETChemistryp Block Elements (Group 13 & 14)
Match the column : ( array |l|l|l|l| & Column-I & & Column-II (A) & Borax & (i) & BN (B) & B ₂ H ₆+ H ₂ O & (ii) & B ₂ H ₆ (C) & array c B ₂ H ₆+ NH ₃ (excess) array & (iii) & H ₃ BO ₃ (D) & BCl ₃+ LiAlH ₄ & (iv) & NaBO ₂+ B ₂ O ₃ array )
Options
- AA-iii, B-iv, C-ii, D-i
- BA-ii, B-i, C-iv, D-iii
- CA-i, B-ii, C-iii, D-iv
- DA-iv, B-iii, C-i, D-ii
Correct answer
D. A-iv, B-iii, C-i, D-ii
Step-by-step solution
Matches (Answer: 4) - A) Borax (- ) (iv) ( NaBO ₂+ B ₂ O ₃ ) On strong heating, borax ( Na ₂ ~B ₄ O ₇ 10 H ₂ O ) decomposes to sodium metaborate and boron oxide. ( Na ₂ ~B ₄ O ₇ 2 NaBO ₂+ B ₂ O ₃ ) - B) ( B ₂ H ₆+ H ₂ O ) (iii) ( H ₃ BO ₃ ) Diborane hydrolyzes to boric acid with hydrogen evolution. ( B ₂ H ₆+6 H ₂ O 2 ~B ( OH )₃+6 H ₂ ) - C) ( B ₂ H ₆+ NH ₃ ) (excess) ( ) (i) BN With excess ammonia and heating, diborane ultimately gives boron nitride. ( B ₂ H ₆+2 NH ₃ 2 BN +6 H ₂ (overall) ) - D) ( BCl ₃+ LiAlH ₄ )