NEETChemistryp Block Elements (Group 13 & 14)
A compound (A) of boron reacts with NMe 3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved.
Options
- AA = B 2 H 6 , B = B 2 H 6 ·NMe 3 , C = H 3 BO 3
- BA = B 2 H 6 , B = B 2 H 6 ·NMe 3 , C = HBO 2
- CA = B 2 H 6 ·NMe 3 , B = B 2 H 6 , C = HBO 2
- DA = B 2 H 6 ·NMe 3 , B = B 2 H 6 , C = H 3 BO 3
Correct answer
A. A = B 2 H 6 , B = B 2 H 6 ·NMe 3 , C = H 3 BO 3
Step-by-step solution
Correct Option is : (A) A = B 2 H 6 , B = B 2 H 6 ·NMe 3 , C = H 3 BO 3