But- 2 -yne is reacted separately with one mole of Hydrogen as shown below: B ¯ ← liq NH 3 Na CH 3 - C ≡ + H 2 C - CH 3 → ∆ Pd / C A ¯ Identify the incorrect statements from the options given below: A. A is more soluble than B . B. The boiling point & melting point of A are higher and lower than B respectively. C. A is more polar than B because dipole moment of A is zero. D. Br 2 adds easily to B than A .

Step-by-step solution

A: Cis - But-2-ene B: Trans - But-2-ene More polar molecules are more soluble in H 2 O . Hence A >B. Molecules having higher dipole moments have higher boiling points due to larger intermolecular forces of attraction. More symmetric isomers have higher melting points due to better packing in crystalline lattice & trans isomers are more symmetric than cis. Hence, in case of boiling point it is A>B and in case of melting point it is B>A. cis-isomer has resultant of dipoles while in trans isomer dipole moments cancel