NEETChemistryHydrocarbons
The intermediate carbocation formed in the reactions of HI, HBr and HCl with propene is the same and the bond energy of HCl, HBr and HI is 430.5 kJ mol –1 , 363.7 kJ mol –1 and 296.8 kJ mol –1 respectively. What will be the order of reactivity of these halogen acids?
Options
- ABond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI > HBr
- BBond dissociation energy is maximum for HI and minimum for HCl, therefore, order of reactivity will be HI < HB
- CBond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI = HBr
- DBond dissociation energy is least for HCl and maximum for HBr, therefore, order of reactivity will be HCl > HI
Correct answer
A. Bond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI > HBr
Step-by-step solution
Correct Option is : (A) Bond dissociation energy is least for HI and maximum for HCl, therefore, order of reactivity will be HI > HBr > HCl.