Consider the following reaction sequence: 2 -Bromopentane alc. KOH, A (Major product) A [ (ii) Zn/H ₂ O ] (i) O ₃ B + C Identify the IUPAC names of the final products B and C.

Step-by-step solution

Reaction of 2 -bromopentane with alcoholic KOH undergoes -elimination (dehydrohalogenation). According to Zaitsev's rule, the more substituted alkene is the major product. Thus, the major product A is pent- 2 -ene. Reductive ozonolysis of pent- 2 -ene (C H₃ -CH=CH-CH₂ -CH₃ ) cleaves the double bond to form two aldehyde molecules. CH₃ -CH=CH-CH₂ -CH₃ O ₃, Zn/H ₂ O CH₃ CHO + CH₃ CH₂ CHO Hence, the products B and C are Ethanal and Propanal. Methanal and Butanal would be formed from the minor product (pent- 1 -ene). Et