Reductive ozonolysis of an alkene yields propanone and ethanal as the products. The IUPAC name of the alkene is

Step-by-step solution

The products of reductive ozonolysis are propanone ( CH ₃ COCH ₃ ) and ethanal ( CH ₃ CHO ). To find the structure of the original alkene, remove the oxygen atoms from the carbonyl groups and join the corresponding carbon atoms with a double bond. CH ₃- C ( CH ₃)= O + O = CH - CH ₃ CH ₃- C ( CH ₃)= CH - CH ₃ Numbering the longest carbon chain to give the double bond the lowest possible number, we get 2-methylbut-2-ene. 2-Methylbut-1-ene yields butan-2-one and methanal. 3-Methylbut-1-ene yields 2-methylpropanal and