NEETChemistryHydrocarbons
An aromatic compound 'X' reacts with I ₂ and NaOH to give a yellow precipitate and the sodium salt of an acid 'Y'. Acid 'Y' on heating with soda lime produces benzene. Compound 'X' can be synthesized by the reaction of benzene with reagent 'Z' in the presence of anhydrous AlCl ₃ . Identify compound 'X' and reagent 'Z'.
Options
- A'X' is Benzaldehyde and 'Z' is Formyl chloride
- B'X' is Acetophenone and 'Z' is Acetyl chloride
- C'X' is Propiophenone and 'Z' is Propanoyl chloride
- D'X' is Toluene and 'Z' is Methyl chloride
Correct answer
B. 'X' is Acetophenone and 'Z' is Acetyl chloride
Step-by-step solution
Acid 'Y' undergoes decarboxylation on heating with soda lime ( NaOH and CaO ) to produce benzene, which indicates that 'Y' is benzoic acid ( C ₆ H ₅ COOH ). The sodium salt of 'Y' is sodium benzoate. Compound 'X' reacts with I ₂ and NaOH to form sodium benzoate and a yellow precipitate (iodoform, CHI ₃ ). This positive iodoform test indicates that 'X' is a methyl ketone, specifically acetophenone ( C ₆ H ₅ COCH ₃ ). Acetophenone ('X') is synthesized by the Friedel-Crafts acylation of benzene using acetyl chloride (