NEETChemistryHydrocarbons
Match List I with List II for the products obtained upon reductive ozonolysis ( O₃/Zn, H₂O ) of the given alkenes. (A) 2-Methylpropene (I) Propanone and Ethanal (B) But-2-ene (II) Propanone and Methanal (C) Cyclopentene (III) Pentanedial (D) 2-Methylbut-2-ene (IV) Ethanal only Choose the correct answer from the options given below:
Options
- A(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
- B(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
- C(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
- D(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
Correct answer
D. (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
Step-by-step solution
Reductive ozonolysis of alkenes cleaves the C=C double bond to form carbonyl compounds. (A) 2-Methylpropene ( (CH₃)₂C=CH₂ ) has a terminal double bond and yields propanone and methanal. (B) But-2-ene ( CH₃-CH=CH-CH₃ ) is a symmetrical internal alkene and yields two moles of ethanal. (C) Cyclopentene is a cyclic alkene. Cleavage of the ring yields a single molecule with two aldehyde groups, pentanedial ( OHC-CH₂-CH₂-CH₂-CHO ). (D) 2-Methylbut-2-ene ( (CH₃)₂C=CH-CH₃ ) has an internal double bond with one branched car