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Match List-I with List-II. List-I (Reactions of Benzene) List-II (Major Product) (A) With 3 Cl ₂ in presence of UV light at 500 K (I) Hexachlorobenzene (B) With excess Cl ₂ in presence of anhydrous AlCl ₃ in dark (II) Benzene hexachloride (C) With 3 H ₂ in presence of Ni at high temperature and pressure (III) Cyclohexane (D) With CH ₃ Cl in presence of anhydrous AlCl ₃ (IV) Toluene Choose the correct answer from the

Options

  1. A(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  2. B(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  3. C(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  4. D(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

Correct answer

C. (A)-(II), (B)-(I), (C)-(III), (D)-(IV)

Step-by-step solution

(A) Benzene reacts with chlorine in the presence of UV light to undergo free radical addition, forming benzene hexachloride ( C ₆ H ₆ Cl ₆ ). So, (A) matches with (II). (B) Benzene reacts with excess chlorine in the presence of anhydrous AlCl ₃ (a Lewis acid) in the dark to undergo electrophilic substitution, forming hexachlorobenzene ( C ₆ Cl ₆ ). So, (B) matches with (I). (C) Benzene undergoes catalytic hydrogenation with 3 H ₂ in the presence of finely divided nickel at high temperature and pressure to form cycl

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