NEETChemistryHydrocarbons
Match List-I with List-II. List-I List-II A. Alkyl halide heated with alc. KOH to form an alkene I. Dehydration B. Alcohol heated with conc. H₂ SO₄ to form an alkene II. Zaitsev's rule C. Rule stating that the major product is the more substituted alkene III. Dehydrohalogenation D. Reaction involving removal of a proton from the carbon adjacent to the halogen-bearing carbon IV. -elimination Choose the correct answer
Options
- AA-I, B-III, C-II, D-IV
- BA-III, B-I, C-IV, D-II
- CA-IV, B-II, C-III, D-I
- DA-III, B-I, C-II, D-IV
Correct answer
D. A-III, B-I, C-II, D-IV
Step-by-step solution
A. Heating an alkyl halide with alcoholic KOH results in the removal of a hydrogen atom and a halogen atom (HX), which is termed Dehydrohalogenation (A-III). B. Heating an alcohol with concentrated H₂ SO₄ results in the loss of a water molecule, which is termed Dehydration (B-I). C. The rule that governs the formation of the more alkylated (substituted) alkene as the major product in elimination reactions is Zaitsev's rule (C-II). D. The removal of a hydrogen atom from the -carbon (the carbon adjacent to the one ca