An element germanium crystallises in b c c type crystal structure with edge of unit cell equal to 288 pm and the density of the element equal to 7.2 ~g ~cm ⁻³ . The number of atoms present in 52 ~g of the crystalline element and the atomic mass of the element are respectively

Step-by-step solution

d=7.2 ~g ~cm ⁻³, a=288 pm and mass of element =52 ~g Hence, d= Mass Volume 7.2 ~g ~cm ⁻³= 52 ~g V V= 52 ~g 7.2 ~g ~cm ⁻³ =7.222 ~cm ^3 Edge of unit cell, a=288 pm =288 10⁻¹² ~m =288 10⁻¹⁰ ~cm =2.88 10⁻⁸ ~cm Volume of unit cell, a^3= (2.88 10⁻⁸ ~cm )^3=23.888 10⁻²⁴ ~cm ^3 The number of unit cells in 52 ~g of metal aligned & = Total volume Volume of one unit cell & = 7.222 ~cm ^3 23.888 10⁻²⁴ ~cm ^3 =0.3023 10²⁴ aligned Germanium has body centred cubic structure. Hence, its unit cell contains 2 atoms. Total atoms in