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If a solution of CuSO 4 is electrolyzed for 10 minutes with a current of 1.5 amperes, what is the mass of copper deposited at the cathode?

Options

  1. A0.0387 g
  2. B0.1935 g
  3. C0.2938 g
  4. D0.4271 g

Correct answer

C. 0.2938 g

Step-by-step solution

The mass of copper deposited can be calculated using Faraday's laws of electrolysis and the given conditions of current and time. Given, t = 600 s charge = current × time = 1.5 A × 600 s = 900 C According to the reaction: Cu2+(aq) + 2e– = Cu(s) We require 2F or 2 × 96487 C to deposit 1 mol or 63 g of Cu. For 900 C, the mass of Cu deposited = (63 g mol-1 × 900

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