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What is the formula for the cell potential (E (cell) ) in a Daniell cell when expressed using base 10 logarithm and given R = 8.314, F = 96487, and T = 298 K?

Options

  1. AE (cell) = Eo (cell) - 0.059/2 log [Zn2+] / [Cu2+]
  2. BE (cell) = Eo (cell) - 0.298/2 log [Cu2+] / [Zn2+]
  3. CE (cell) = Eo (cell) - 0.059/2 log [Cu2+] / [Zn2+]
  4. DE (cell) = Eo (cell) - 0.298/2 log [Zn2+] / [Cu2+]

Correct answer

A. E (cell) = Eo (cell) - 0.059/2 log [Zn2+] / [Cu2+]

Step-by-step solution

When expressed using base 10 logarithm and with the provided values of R, F, and T, the formula for the cell potential (E (cell) ) in a Daniell cell is E (cell) = Eo (cell) - 0.059/2 log [Zn2+] / [Cu2+].

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