NEETChemistryElectrochemistry
What is the formula for the cathode electrode potential (E) in a Daniell cell for Zn2+ ions?
Options
- AE(Cu2+/Cu) = Eo(Cu2+/Cu) - RT/2F ln 1/ [Cu2+ (aq)]
- BE(Cu / Cu2+) = Eo(Cu / Cu2+) - RT/2F ln 1/ [Cu2+ (aq)]
- CE(Zn2+/Zn) = Eo(Zn2+/Zn) - RT/2F ln 1/[Zn2+ (aq)]
- DE(Zn/Zn2+) = Eo(Zn/Zn2+) - RT/2F ln 1/[Zn2+ (aq)]
Correct answer
C. E(Zn2+/Zn) = Eo(Zn2+/Zn) - RT/2F ln 1/[Zn2+ (aq)]
Step-by-step solution
The formula for the cathode electrode potential in a Daniell cell for Zn2+ ions is given as E(Zn2+/Zn) = Eo(Zn2+/Zn) - RT/2F ln 1/ [Zn2+ (aq)].