NEETChemistryElectrochemistry
What is the measured emf of the cell with the representation Pt(s) |H2(g, 1 bar) |H+(aq, 1 M) | |Cu2+ (aq,1 M) | Cu?
Options
- A0.34 V
- B1.10 V
- C-0.76 V
- D1.44 V
Correct answer
A. 0.34 V
Step-by-step solution
The measured emf of the cell:Pt(s) |H2(g, 1 bar) |H+(aq, 1 M) | |Cu2+ (aq,1 M) | Cu is 0.34 V and it is also the value for the standard electrode potential of the half-cell corresponding to the reaction: Cu2+ (aq, 1M) + 2 e- → Cu(s).