NEETChemistryElectrochemistry
What is the measured emf of the cell with the representation Pt(s) | H2(g, 1 bar) | H+(aq, 1 M) | | Zn2+ (aq, 1M) | Zn?
Options
- A0.34 V
- B1.10 V
- C-0.76 V
- D-1.44 V
Correct answer
C. -0.76 V
Step-by-step solution
The measured emf of the cell: Pt(s) | H2(g, 1 bar) | H+(aq, 1 M) | | Zn2+ (aq, 1M) | Zn is -0.76 V corresponding to the standard electrode potential of the half-cell reaction: Zn2+ (aq, 1 M) + 2e- → Zn(s).