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Calculate the emf of the cell in which the following reaction takes place Ni(s) + 2Ag⁺ (0.002 M) → Ni²⁺ (0.160 M) + 2Ag(s) Given that E(cell) = 1.05 V

Options

  1. A1.05 V
  2. B0.85 V
  3. C0.65 V
  4. D1.25 V

Correct answer

B. 0.85 V

Step-by-step solution

Correct Option is : (B) 0.85 V

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