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Consider the figure given: If cell ‘A’ has E Cell = 0.5 V and cell ‘B’ has E Cell = 1.1 V then what will be the reactions at anode and cathode?

Options

  1. AAt cathode : Zn → Zn 2+ + 2e – and Cu 2+ + 2e – → Cu
  2. BAt cathode : Zn → Zn 2+ + 2e – and at anode : Cu 2+ + 2e – → Cu
  3. CAt anode : Zn → Zn 2+ + 2e – and Cu 2+ + 2e – → Cu
  4. DAt anode : Zn → Zn 2+ + 2e – and at cathode : Cu 2+ + 2e – → Cu

Correct answer

D. At anode : Zn → Zn 2+ + 2e – and at cathode : Cu 2+ + 2e – → Cu

Step-by-step solution

Correct Option is : (D) At anode : Zn → Zn 2+ + 2e – and at cathode : Cu 2+ + 2e – → Cu

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