The limiting molar conductivities of Ba(OH) ₂ , BaCl ₂ and NH ₄ Cl are given as x , y and z S cm ^2 mol ⁻¹ respectively. The limiting molar conductivity of NH ₄ OH in S cm ^2 mol ⁻¹ will be:

Step-by-step solution

According to Kohlrausch's law of independent migration of ions: _m^0( Ba(OH) ₂) = ^0_ Ba ²⁺ + 2 ^0_ OH ^- = x _m^0( BaCl ₂) = ^0_ Ba ²⁺ + 2 ^0_ Cl ^- = y _m^0( NH ₄ Cl ) = ^0_ NH ₄^+ + ^0_ Cl ^- = z Subtracting the second equation from the first gives: x - y = 2 ^0_ OH ^- - 2 ^0_ Cl ^- ^0_ OH ^- - ^0_ Cl ^- = x - y 2 The limiting molar conductivity for NH ₄ OH is: _m^0( NH ₄ OH ) = ^0_ NH ₄^+ + ^0_ OH ^- This can be rewritten as: _m^0( NH ₄ OH ) = ( ^0_ NH ₄^+ + ^0_ Cl ^- ) + ( ^0_ OH ^- - ^0_ Cl ^- ) _m^0( NH ₄ OH