The limiting molar conductivities ( _ m ^ ) of some strong electrolytes are given below: Electrolyte _ m ^ / S~cm ^2~ mol ⁻¹ CH₃COONa 90 HCl 425 NaCl 115 If the molar conductivity of a 0.02~ mol~L ⁻¹ solution of acetic acid ( CH₃COOH ) is 48~ S~cm ^2~ mol ⁻¹ , its degree of dissociation is:

Step-by-step solution

According to Kohlrausch's law of independent migration of ions, the limiting molar conductivity of acetic acid ( CH₃COOH ) can be calculated from the given strong electrolytes: _ m ^ ( CH₃COOH ) = _ m ^ ( CH₃COONa ) + _ m ^ ( HCl ) - _ m ^ ( NaCl ) _ m ^ ( CH₃COOH ) = 90 + 425 - 115 = 400~ S~cm ^2~ mol ⁻¹ The degree of dissociation ( ) is the ratio of molar conductivity at a given concentration to the limiting molar conductivity: = _ m _ m ^ = 48 400 = 0.12 Adding all three values incorrectly yields 630 , giving 0.