A conductivity cell with a cell constant of 0.4 cm ⁻¹ is filled with a 0.02 M solution of an electrolyte. If the measured resistance of the cell is 100 , the molar conductivity of the solution is:

Step-by-step solution

First, calculate the conductivity ( ) of the solution using the cell constant ( G^* ) and resistance ( R ): = G^* R = 0.4 cm ⁻¹ 100 = 4 10⁻³ S cm ⁻¹ Next, calculate the molar conductivity ( _m ) using the formula: _m = 1000 C Substituting the values: _m = 4 10⁻³ 1000 0.02 = 4 0.02 = 200 S cm ^2 mol ⁻¹ Answer: 200 S cm ^2 mol ⁻¹