NEETChemistryElectrochemistry
Match List-I with List-II based on Kohlrausch's law of independent migration of ions. List-I List-II (A) _ m ^ ( CH ₃ COONa ) + _ m ^ ( HCl ) - _ m ^ ( NaCl ) (I) NH ₄ OH (B) _ m ^ ( NH ₄ Cl ) + _ m ^ ( NaOH ) - _ m ^ ( NaCl ) (II) AgCl (C) 1 2 _ m ^ ( CaCl ₂) + _ m ^ ( AgNO ₃) - 1 2 _ m ^ ( Ca(NO ₃)₂) (III) NaCl (D) _ m ^ ( NaBr ) + _ m ^ ( KCl ) - _ m ^ ( KBr ) (IV) CH ₃ COOH Choose the correct answer from the opti
Options
- A(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
- B(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
- C(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
- D(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
Correct answer
D. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
Step-by-step solution
According to Kohlrausch's law, the limiting molar conductivity of an electrolyte can be represented as the sum of the individual contributions of the anion and cation of the electrolyte. (A) _ m ^ ( CH ₃ COONa ) + _ m ^ ( HCl ) - _ m ^ ( NaCl ) = ^ ( CH ₃ COO ^-) + ^ ( H ^+) = _ m ^ ( CH ₃ COOH ) (B) _ m ^ ( NH ₄ Cl ) + _ m ^ ( NaOH ) - _ m ^ ( NaCl ) = ^ ( NH ₄^+) + ^ ( OH ^-) = _ m ^ ( NH ₄ OH ) (C) 1 2 _ m ^ ( CaCl ₂) + _ m ^ ( AgNO ₃) - 1 2 _ m ^ ( Ca(NO ₃)₂) = ^ ( Cl ^-) + ^ ( Ag ^+) = _ m ^ ( AgCl ) (D) _ m ^