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The limiting molar conductivities of NH ₄ OH , NH ₄ Cl and NaOH are 271.6 , 149.7 and 248.1 S cm ^2 mol ⁻¹ respectively. What is the limiting molar conductivity of NaCl ?

Options

  1. A126.2 S cm ^2 mol ⁻¹
  2. B173.2 S cm ^2 mol ⁻¹
  3. C370.0 S cm ^2 mol ⁻¹
  4. D669.4 S cm ^2 mol ⁻¹

Correct answer

A. 126.2 S cm ^2 mol ⁻¹

Step-by-step solution

According to Kohlrausch's law of independent migration of ions: ^ _m( NH ₄ OH ) = ^ _m( NH ₄ Cl ) + ^ _m( NaOH ) - ^ _m( NaCl ) Rearranging the equation to solve for ^ _m( NaCl ) : ^ _m( NaCl ) = ^ _m( NH ₄ Cl ) + ^ _m( NaOH ) - ^ _m( NH ₄ OH ) Substituting the given values: ^ _m( NaCl ) = 149.7 + 248.1 - 271.6 ^ _m( NaCl ) = 397.8 - 271.6 = 126.2 S cm ^2 mol ⁻¹ Answer: 126.2 S cm ^2 mol ⁻¹

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