NEET2013ChemistryElectrochemistryActual
A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH =10 and by passing hydrogen gas around the platinum wire at 1 ~atm pressure. The oxidation potential of electrode would be
Options
- A0.059 ~V
- B0.59 ~V
- C0.118 ~V
- D1.18 ~V
Correct answer
B. 0.59 ~V
Step-by-step solution
For hydrogen electrode, oxidation half reaction is (1 ~atm ) H ₂ ( At pH~ 10) 2 H ⁺ +2 e ⁻ If pH =10 H ⁺=1 10^ - pH =1 10⁻¹⁰ From Nernst equation, E_ cell =E_ cell ^0- 0.0591 2 [ H ⁺ ]^2 P_ H ₂ For hydrogen electrode, E_ cell ^ =0 aligned E_ cell & =- 0.0591 2 (10⁻¹⁰ )^2 1 & =+ 0.0591 2 2 1 10⁻¹⁰ & =0.0591 10¹⁰ & =0.0591 10=0.591 ~V aligned