Given, (i) Cu ²⁺+2 e ⁻ Cu , E ^ =0.337 ~V (ii) Cu ²⁺+ e ⁻ Cu ⁺ , E ^ =0.153 ~V Electrode potential, E ^ for the reaction, Cu + e ⁻ Cu , will be

Step-by-step solution

Key Idea Gibb's free energy is an additive property. G ^ =- nFE ^ For reaction, Cu ²⁺+2 e ⁻ Cu ; G^ =-2 F 0.337 For reaction, Cu ⁺ Cu ²⁺+ e ⁻ ; G ^ =+1 F 0.153 Adding Eqs. (i) and (ii), we get gathered Cu ⁺+ e ⁻ Cu ; G ^ =-0.521 G ^ =- nFE ^ -0.521 ~F =- nFE ^ E ^ =0.52 ~V gathered