The e.m.f. of a Deniell cell at 298 ~K is E ₁ Zn | array c ZnSO ₄ (0.01 M ) array | | array c CuSO ₄ (0.01 M ) array | Cu When the concentration of ZnSO ₄ in 1.0 M and that of CuSO ₄ is 0.01 M , the e.m.f. changed to E ₂ . What is the relat

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The e.m.f. of a Deniell cell at 298 ~K is E ₁ Zn | array c ZnSO ₄ (0.01 M ) array | | array c CuSO ₄ (0.01 M ) array | Cu When the concentration of ZnSO ₄ in 1.0 M and that of CuSO ₄ is 0.01 M , the e.m.f. changed to E ₂ . What is the relationship between E₁ and E₂ ?

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Correct answer: A. E ₁> E ₂

Cell reaction can be represented as: Zn + Cu ²⁺ Ca + Zn ²⁺ Applying in both cases, E ^0= -0.0591 2 Zn ²⁺ C ²⁺ Thus, E ₁> E ₂

The e.m.f. of a Deniell cell at 298 ~K is E ₁ Zn | array c ZnSO ₄ (0.01 M ) array | | array c CuSO ₄ (0.01 M ) array | Cu When the concentration of ZnSO ₄ in 1.0 M and that of CuSO ₄ is 0.01 M , the e.m.f. changed to E ₂ . What is the relationship between E₁ and E₂ ?

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