Hydrofluoric acid is a weak acid. At 25^ C , the molar conductivity of 0.002 M HF is 176.2 ⁻¹ ~cm ^2 ~mol ⁻¹ . If its _m^ =405.2 ⁻¹ ~cm ^2 ~mol ⁻¹ . Equilibrium constant at the given concentration is

Step-by-step solution

aligned & = _c _m^ = 176.2 ⁻¹ ~cm ^2 ~mol ⁻¹ 405.2 ⁻¹ ~cm ^2 ~mol ⁻¹ =0.435 K & = [ H ⁺ ] [ F ⁻¹ ] [ HF ] = C ^2 1- = (0.002 M )(0.435)^2 1-0.435 =6.7 10⁻⁴ M & =6.70 10⁻⁴ M . aligned