One gram sample of NH_4 NO_3 is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12 ~K . The heat capacity of the system is 1.23 ~kJ / g / deg . What is the molar heat of decomposition

Correct answer: D. -602 ~kJ / mol Heat of decomposition, Δ E=m s Δ T =1 × 1.23 × 6.12=7.5276 kJ . Molar heat of decomposition for NH_4 NO_3 = 7.5276 × 80=602.2 kJ / mol

AIIMS 2003

Exam: AIIMS
Year: 2003
Subject: Chemistry
Chapter: Thermodynamics (C)

AIIMS 2003 · Chemistry · Thermodynamics (C)

One gram sample of NH_4 NO_3 is decomposed in a bomb calorimeter....

One gram sample of

\mathrm{NH}_4 \mathrm{NO}_3

is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by

6.12 \mathrm{~K}

. The heat capacity of the system is

1.23 \mathrm{~kJ} / \mathrm{g} / \mathrm{deg}

. What is the molar heat of decomposition for

\mathrm{NH}_4 \mathrm{NO}_3

Options

A $-7.53 \mathrm{~kJ} / \mathrm{mol}$
B $-398.1 \mathrm{~kJ} / \mathrm{mol}$
C $-16.1 \mathrm{~kJ} / \mathrm{mol}$
D $-602 \mathrm{~kJ} / \mathrm{mol}$

Correct answer

D. $-602 \mathrm{~kJ} / \mathrm{mol}$

Step-by-step solution

Heat of decomposition,

\Delta E=m s \Delta T

=1 \times 1.23 \times 6.12=7.5276

\mathrm{ kJ} \text{. }

Molar heat of decomposition for

\mathrm{NH}_4 \mathrm{NO}_3 =

7.5276 \times 80=602.2

\mathrm{ kJ}

\mathrm{mol}

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