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NEET 2004
Exam
NEET
Year
2004
Subject
Chemistry
Chapter
Thermodynamics (C)

NEET 2004 · Chemistry · Thermodynamics (C)

The work done during expansion of a gas from a volume of 4 dm^3 to...

The work done during expansion of a gas from a volume of 4dm34 \mathrm{dm}^3 to 6dm36 \mathrm{dm}^3 against a constant external pressure of 3 atm3 \mathrm{~atm} is (1 L atm=101.32 J)(1 \mathrm{~L} \mathrm{~atm}=101.32 \mathrm{~J}) :

Options

  1. A−6 J-6 \mathrm{~J}
  2. B−608 J-608 \mathrm{~J}
  3. C+304 J+304 \mathrm{~J}
  4. D−304 J-304 \mathrm{~J}

Correct answer

B. −608 J-608 \mathrm{~J}

Step-by-step solution

Work =−Pext×=-P_{e x t} \times volume change =3×101.32×(6−4)=6×101.32=−607.92 J=−608 J\begin{aligned}& =3 \times101.32 \times(6-4) \\ & =6 \times101.32 \\ & =-607.92 \mathrm{~J}=-608 \mathrm{~J} \end{aligned}
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