NEETChemistryHaloalkanes and Haloarenes
The correct answer is
Options
- A(a)
- B(b)
- C(c)
- D(d)
Correct answer
D. (d)
Step-by-step solution
(A) CH ₃- CHBr - CH ₂ Br KOH / C ₂ H ₅ OH (IV) Alkenyl bromide. KOH ( alc.) will remove one H and one Br to give aIkenyl bromide. (B) CCC=CCCOCC gives 1^ alkyl bromide due to presence of peroxide and HBr. (Anti-markownikoff's addition) (C) CH ₃- CH ₂- CH ₃ Br ₂ , hv (II), gives 2^ alkyl bromide because 2^ carbocation is more stable. (D) CH ₃- CH = CH ₂ NBS (III) gives allyI bromide due to presence of NBS. Hence, option (4) is the correct answer.