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NEETChemistryHaloalkanes and Haloarenes

Primary alkyl halide C 4 H 9 Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C 8 H 18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the IUPAC name of (a)

Options

  1. A1−bromo−1−methylpropane
  2. B2−bromo−1−methylpropane
  3. C1−bromo−3−methylpropane
  4. D2−bromo−2−methylpropane

Correct answer

D. 2−bromo−2−methylpropane

Step-by-step solution

Correct Option is : (D) 2−bromo−2−methylpropane

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