NEETChemistryHaloalkanes and Haloarenes
tert-Butyl Bromide reacts with aq. NaOH by S N 1 mechanism while n-butyl bromide reacts by S N 2 mechanism. Why?
Options
- AAs tert. Carbocation is highly stable so tert-butyl bromide follows S N 1 mechanism.In case of n-butylbromide,
- Btert-Butyl Bromide forms a stronger bond with the nucleophile.
- Cn-Butyl bromide has a more stable carbocation intermediate.
- Dn-Butyl bromide has a more bulky structure.
Correct answer
A. As tert. Carbocation is highly stable so tert-butyl bromide follows S N 1 mechanism.In case of n-butylbromide,
Step-by-step solution
Correct Option is : (A) As tert. Carbocation is highly stable so tert-butyl bromide follows S N 1 mechanism.In case of n-butylbromide,primary carbocation is formed which is least stable so it does not follow S N 1 mechanism. Here, steric hindrance is very less, so it follows S N 2 mechanism.