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NEET2009ChemistryHaloalkanes and HaloarenesActual

2-Phenylethylbromide when heated with NaOEt , elimination takes place. No deuterium exchange takes place when the reaction is carried out in C ₂ H ₅ OD solvent. The mechanism will be

Options

  1. AE1 elimination
  2. BE2 elimination
  3. CE1cB elimination
  4. DE 2 or E1cB.

Correct answer

B. E2 elimination

Step-by-step solution

It is a primary bromide. So it will undergo elimination either by E2 or E1cB. Since there is no deuterium exchange in C ₂ H ₅ OD solvent, C - H bond is not broken to form carbanion. Hence the actual mechanism is E2 only.

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