Assertion : Alkyl iodide can be prepared by treating alkyl chloride/bromide with ( NaI ) in acetone. Reason : ( NaCl / NaBr ) are soluble in acetone while ( NaI ) is not.

Step-by-step solution

This is Finkelstein reaction which involves the conversion of an alkyl chloride/bromide to an alkyl iodide by the addition of sodium iodide in acetone. Because sodium iodide is soluble in acetone and ( NaCl ) and ( NaBr ) are not, the equilibrium is shifted by the precipitation of insoluble salt. (R-X M X M X^ R-X^ ) The equilibrium position of the reaction depends on the nucleophilicity of the anion, whether a good leaving group is present and whether one anion is better stabilised than the other in a given solven