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NEET
Exam
NEET
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

NEET · Chemistry · Carboxylic Acid Derivatives

A secondary alcohol 'P' on oxidation with CrO_3 gives compound 'Q'....

A secondary alcohol 'P' on oxidation with CrO3\mathrm{CrO_3} gives compound 'Q'. Compound 'Q' can also be synthesized by the reaction of benzene with propanoyl chloride in the presence of anhydrous AlCl3\mathrm{AlCl_3}. Identify the alcohol 'P'.

Options

  1. A1-Phenylpropan-2-ol
  2. B1-Phenylpropan-1-ol
  3. C3-Phenylpropan-1-ol
  4. D2-Phenylpropan-2-ol

Correct answer

B. 1-Phenylpropan-1-ol

Step-by-step solution

The reaction of benzene with propanoyl chloride (CH3CH2COCl\mathrm{CH_3CH_2COCl}) in the presence of anhydrous AlCl3\mathrm{AlCl_3} is a Friedel-Crafts acylation. It yields propiophenone (1-phenylpropan-1-one) as compound 'Q'.

Compound 'Q' is also formed by the oxidation of a secondary alcohol 'P' with CrO3\mathrm{CrO_3}. Therefore, 'P' must be the secondary alcohol corresponding to propiophenone.

Reducing the ketone group of 1-phenylpropan-1-one gives 1-phenylpropan-1-ol. Thus, 'P' is 1-phenylpropan-1-ol.

1-Phenylpropan-2-ol would oxidize to 1-phenylpropan-2-one. 3-Phenylpropan-1-ol is a primary alcohol, and 2-phenylpropan-2-ol is a tertiary alcohol which resists oxidation.

Answer: 1-Phenylpropan-1-ol
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