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- Carboxylic Acid Derivatives
NEET · Chemistry · Carboxylic Acid Derivatives
A secondary alcohol 'P' on oxidation with CrO_3 gives compound 'Q'....
A secondary alcohol 'P' on oxidation with gives compound 'Q'. Compound 'Q' can also be synthesized by the reaction of benzene with propanoyl chloride in the presence of anhydrous . Identify the alcohol 'P'.
Options
- A1-Phenylpropan-2-ol
- B1-Phenylpropan-1-ol
- C3-Phenylpropan-1-ol
- D2-Phenylpropan-2-ol
Correct answer
B. 1-Phenylpropan-1-ol
Step-by-step solution
The reaction of benzene with propanoyl chloride () in the presence of anhydrous is a Friedel-Crafts acylation. It yields propiophenone (1-phenylpropan-1-one) as compound 'Q'.
Compound 'Q' is also formed by the oxidation of a secondary alcohol 'P' with . Therefore, 'P' must be the secondary alcohol corresponding to propiophenone.
Reducing the ketone group of 1-phenylpropan-1-one gives 1-phenylpropan-1-ol. Thus, 'P' is 1-phenylpropan-1-ol.
1-Phenylpropan-2-ol would oxidize to 1-phenylpropan-2-one. 3-Phenylpropan-1-ol is a primary alcohol, and 2-phenylpropan-2-ol is a tertiary alcohol which resists oxidation.
Answer: 1-Phenylpropan-1-ol
Compound 'Q' is also formed by the oxidation of a secondary alcohol 'P' with . Therefore, 'P' must be the secondary alcohol corresponding to propiophenone.
Reducing the ketone group of 1-phenylpropan-1-one gives 1-phenylpropan-1-ol. Thus, 'P' is 1-phenylpropan-1-ol.
1-Phenylpropan-2-ol would oxidize to 1-phenylpropan-2-one. 3-Phenylpropan-1-ol is a primary alcohol, and 2-phenylpropan-2-ol is a tertiary alcohol which resists oxidation.
Answer: 1-Phenylpropan-1-ol