NEETChemistryCarboxylic Acid Derivatives
Match the alkenes in List-I with their respective major products obtained upon vigorous oxidation with hot acidic KMnO ₄ in List-II. List-I (Alkene) List-II (Oxidation Products) A. 2-Methylbut-2-ene I. Butanedioic acid B. Pent-2-ene II. Ethanoic acid and Propanoic acid C. 3,3-Dimethylbut-1-ene III. Propanone and Ethanoic acid D. Cyclobutene IV. 2,2-Dimethylpropanoic acid and CO ₂ Choose the correct answer from the op
Options
- AA-II, B-III, C-IV, D-I
- BA-III, B-II, C-I, D-IV
- CA-III, B-IV, C-II, D-I
- DA-III, B-II, C-IV, D-I
Correct answer
D. A-III, B-II, C-IV, D-I
Step-by-step solution
Vigorous oxidation of alkenes with hot acidic KMnO ₄ leads to the cleavage of the C = C double bond. A. 2-Methylbut-2-ene ( CH ₃- C ( CH ₃)= CH - CH ₃ ) has one vinylic carbon with no hydrogen and one with a hydrogen. It cleaves to form a ketone (propanone) and a carboxylic acid (ethanoic acid). (A III) B. Pent-2-ene ( CH ₃- CH ₂- CH = CH - CH ₃ ) is an internal alkene with hydrogens on both vinylic carbons. It cleaves to form propanoic acid and ethanoic acid. (B II) C. 3,3-Dimethylbut-1-ene ( ( CH ₃)₃ C - CH = CH