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NEETChemistryCarboxylic Acid Derivatives

Match List I with List II: List I (Reaction) List II (Product Property) (A) p -Methoxytoluene + KMnO ₄/ H ^+ (I) Product is a stronger acid than benzoic acid (B) p -Chlorotoluene + KMnO ₄/ H ^+ (II) Product is a weaker acid than benzoic acid (C) p -Nitroanisole + Sn / HCl (III) Product is a stronger base than aniline (D) p -Chloronitrobenzene + Sn / HCl (IV) Product is a weaker base than aniline Choose the correct an

Options

  1. A(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  2. B(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
  3. C(A)-(II), (B)-(II), (C)-(III), (D)-(III)
  4. D(A)-(I), (B)-(I), (C)-(IV), (D)-(IV)

Correct answer

A. (A)-(II), (B)-(I), (C)-(III), (D)-(IV)

Step-by-step solution

(A) Oxidation of p -methoxytoluene with acidic KMnO ₄ yields p -methoxybenzoic acid. The - OCH ₃ group has a strong +M effect which outweighs its -I effect, making the product a weaker acid than benzoic acid. (Matches II) (B) Oxidation of p -chlorotoluene yields p -chlorobenzoic acid. For halogens, the -I effect outweighs the +M effect, making the product a stronger acid than benzoic acid. (Matches I) (C) Reduction of p -nitroanisole with Sn / HCl yields p -anisidine. The +M effect of the - OCH ₃ group increases el

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