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NEET
Exam
NEET
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

NEET · Chemistry · Carboxylic Acid Derivatives

Match List I with List II: List I (Reaction) List II (Product...

Match List I with List II:

List I (Reaction)List II (Product Property)
(A) pp-Methoxytoluene + KMnO4/H+\text{KMnO}_4/\text{H}^+(I) Product is a stronger acid than benzoic acid
(B) pp-Chlorotoluene + KMnO4/H+\text{KMnO}_4/\text{H}^+(II) Product is a weaker acid than benzoic acid
(C) pp-Nitroanisole + Sn/HCl\text{Sn}/\text{HCl}(III) Product is a stronger base than aniline
(D) pp-Chloronitrobenzene + Sn/HCl\text{Sn}/\text{HCl}(IV) Product is a weaker base than aniline

Choose the correct answer from the options given below:

Options

  1. A(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  2. B(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
  3. C(A)-(II), (B)-(II), (C)-(III), (D)-(III)
  4. D(A)-(I), (B)-(I), (C)-(IV), (D)-(IV)

Correct answer

A. (A)-(II), (B)-(I), (C)-(III), (D)-(IV)

Step-by-step solution

(A) Oxidation of pp-methoxytoluene with acidic KMnO4\text{KMnO}_4 yields pp-methoxybenzoic acid. The −OCH3-\text{OCH}_3 group has a strong +M+M effect which outweighs its −I-I effect, making the product a weaker acid than benzoic acid. (Matches II)

(B) Oxidation of pp-chlorotoluene yields pp-chlorobenzoic acid. For halogens, the −I-I effect outweighs the +M+M effect, making the product a stronger acid than benzoic acid. (Matches I)

(C) Reduction of pp-nitroanisole with Sn/HCl\text{Sn}/\text{HCl} yields pp-anisidine. The +M+M effect of the −OCH3-\text{OCH}_3 group increases electron density on the nitrogen, making the product a stronger base than aniline. (Matches III)

(D) Reduction of pp-chloronitrobenzene yields pp-chloroaniline. The net electron-withdrawing nature of chlorine (−I>+M-I > +M) decreases electron density on the nitrogen, making the product a weaker base than aniline. (Matches IV)

The correct matching is (A)-(II), (B)-(I), (C)-(III), (D)-(IV).

Answer: (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
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