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AIIMS 201925 May
Exam
AIIMS
Year
2019
Date
25 May
Subject
Physics
Chapter
Electrostatics

AIIMS 2019 · 25 May · Physics · Electrostatics

Four point charges -Q,-q, 2 q and 2 Q are placed, one at each...

Four point charges −Q,−q,2q-Q,-q, 2 q and 2Q2 Q are placed, one at each corner of the square. The relation between QQ and qq for which the potential at the centre of the square is zero is

Options

  1. AQ=−qQ=-q
  2. BQ=−1/qQ=-1 / q
  3. CQ=qQ=q
  4. DQ=1/qQ=1 / q

Correct answer

A. Q=−qQ=-q

Step-by-step solution

Let aa be the side length of the square A B C D..AC=BD=a2+a2=a2OA=OB=OC=OD=a22=a2\begin{aligned} & A C=B D=\sqrt{a^2+a^2}=a \sqrt{2} \\ & O A=O B=O C=O D=\frac{a \sqrt{2}}{2}=\frac{a}{\sqrt{2}}\end{aligned}Potential is a scalar quantity. Potential at the centre $O$ due to given charge configuration is\begin{aligned} & V=\frac{1}{4 \pi \varepsilon_0}\left[\frac{(-Q)}{\left(\frac{a}{\sqrt{2}}\right)}+\frac{(-q)}{\left(\frac{a}{\sqrt{2}}\right)}+\frac{(2 q)}{\left(\frac{a}{\sqrt{2}}\right)}+\frac{2 Q}{\left(\frac{a}{\sqrt{2}}\right)}\right]=0 \\ & \Rightarrow-Q-q+2 q+2 Q=0 \\ & \text{ or } Q+q=0 \text{ or } Q=-q\end{aligned}$$
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