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NEET 2020
Exam
NEET
Year
2020
Subject
Physics
Chapter
Electrostatics

NEET 2020 · Physics · Electrostatics

A spherical conductor of radius 10 cm has a charge of (3.2 × 10^ -7...

A spherical conductor of radius 10 cm has a charge of (3.2 ×\times10^{-7} C\mathrm{C} distributed uniformly. What is the magnitude of electric field at a point 15 cm from the centre of the sphere? (\left(\frac{1}{4 \pi \varepsilon_0}=9 ×\times10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right))

Options

  1. A1.28×105NC−11.28 \times {10}^{5}N{C}^{- 1}
  2. B1.28×106NC−11.28 \times {10}^{6}N{C}^{- 1}
  3. C1.28×107NC−11.28 \times {10}^{7}N{C}^{- 1}
  4. D1.28×104NC−11.28 \times {10}^{4}N{C}^{- 1}

Correct answer

A. 1.28×105NC−11.28 \times {10}^{5}N{C}^{- 1}

Step-by-step solution

E=kQr2=9×109×3.2×10−7(15×10−2)2E = \dfrac{kQ}{{r}^{2}} = \dfrac{9 \times {10}^{9} \times 3 .2 \times {10}^{- 7}}{{\left(15 \times {10}^{- 2}\right)}^{2}}

E=1.28×105NC−1E = 1 . 28 \times {10}^{5}N{C}^{- 1}

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