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AIIMS2015PhysicsElectrostatics

A hexagon of side 8 ~cm has a charge 4 C at each of its vertices. The potential at the centre of the hexagon is

Options

  1. A2.7 10^6 ~V
  2. B7.2 10¹¹ ~V
  3. C2.5 10¹² ~V
  4. D3.4 10^4 ~V

Correct answer

A. 2.7 10^6 ~V

Step-by-step solution

As shown in the figure, O is the centre of hexagon A B C D E F of each side 8 ~cm . As it is a regular hexagon O A B, O B C , etc are equilateral triangles. aligned O A=O B=O C= & O D=O E=O F=8 ~cm & =8 10⁻² ~m aligned The potential at O is aligned V & =6 q 4 ₀ r & = 6 9 10^9 4 10⁻⁶ 8 10⁻² =2.7 10^6 ~V aligned

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